-6t^2+24t=H

Solution for -6t^2+24t=H equation:

-6t^2+24t=

We move all terms to the left:

-6t^2+24t-()=0

We add all the numbers together, and all the variables

-6t^2+24t=0

a = -6; b = 24; c = 0;
Δ = b2-4ac
Δ = 242-4·(-6)·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-24}{2*-6}=\frac{-48}{-12}
=+4
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+24}{2*-6}=\frac{0}{-12}
=0
$